Apabila akar-akar dari persamaan x ^ 2 + bx + c = 0 yaitu -1 dan 3. Maka nilai b yang memenuhi persamaan itu ialah
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Jawaban:
x² + bx + c = 0
(-1)² - b + c = 0
b - c = 1
b = 1 + c
x² + bx + c = 0
(3)² + b(3) + c = 0
3b + c = -9
3(1 + c) + c = -9
3 + 4c = -9
4c = -12
c = -3
x² + bx + c = 0
(-1)² + b(-1) + (-3) = 0
1 - b - 3 = 0
-b = 2
b = -2
Jawab:
b = -2
Penjelasan :
x² + bx + c = 0
a = 1
p = -1, q = 3
Vieta
p + q = -b ÷ a
-1 + 3 = -b ÷ 1
2 = -b ÷ 1
b = 2(-1)
b = -2
(xcvi)
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